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I dont understand this so please explain in details what you do. Thank you8. Write the equilibrium constant for the following reaction in terms of the activities of individual reactants and products. Simplify the expression as much as possible. 2 A(s)+3 B (g)+ 4C )

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Answer #1

Activity of solid and liquid is always taken as unity.

So, Keq = 1/ (\alphaB)3

As Keq = (\alphaC)4 / ((\alphaA)2(\alphaB)3)

But activities of solid and liquids is taken as unity

Hence, Keq = 1/ (\alphaB)3

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