Question

The magnetic field inside a solenoid of circular cross section is given by B⃗ =btk^, where...

The magnetic field inside a solenoid of circular cross section is given by B⃗ =btk^, where b = 3.0 T/ms . At time t = 0.32 μs , a proton is inside the solenoid at x = 5.6 cm ,

y= z=0 , and is moving with velocity v⃗ = 5.0 j^Mm/s .

Part A

Find the electromagnetic force on the proton.

Express your answers using two significant figures separated by commas.

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Answer #1

The magnetic field is 1000 ms (0.32x10 s)k (3.0 T/ms 3000 T/s(0.32 x10 960 x10 k T sk The magnetic force on proton is, qvB -(

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