In a test of hypothesis shown here, the level of significance for the test is .05. The value of the test statistic is Z = 1.8. What is the p-value for this test? | ||||||||||||
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In a test of hypothesis shown here, the level of significance for the test is .05....
In order to conduct a hypothesis test for the population
proportion, you sample 450 observations that result in 189
successes. (You may find it useful to reference the
appropriate table: z table or t
table)
H0: p ≥ 0.45;
HA: p < 0.45.
a-1. Calculate the value of the test statistic.
(Negative value should be indicated by a minus sign. Round
intermediate calculations to at least 4 decimal places and final
answer to 2 decimal places.)
TEST STATISTIC =
a-2....
a) A significance level of = 0.01 is used in testing a researcher's claim that μ > 100 and the sample data give a test statistic of z = 2.03. Determine the rejection region for this test, and then state the decision for such a test. b) A significance level of = 0.05 is used in testing a researcher's claim that μ 100 and the sample data give a test statistic of z = -1.85. Determine the rejection region for...
11. If the null hypothesis is rejected at a 05 significance level, it (a) must also be rejected at a.10 significance level. (b) might also be rejected at a .10 significance level. (c) must not be rejected at a.10 significance level. (d) none of the above lfte null hypothesis İs not rejected at a .05 significance level, it: (a) will also not be rejected at a.01 significance level. (b) might be rejected at a .01 significance level. (e) will be...
A 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is greater than 0.5. Assume that sample data consists of 91 girls in 169 births, so the sample statistic of 7 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below. 13 Click here to view page 1 of the Normal table. Click here...
You are conducting a multinomial hypothesis test (αα = 0.05) for
the claim that all 5 categories are equally likely to be
selected.
Category
Observed
Frequency
A
17
B
11
C
24
D
25
E
25
What is the chi-square test-statistic for this data?
χ2=χ2=
What are the degrees of freedom for this test?
d.f. =
What is the p-value for this sample? (Report answer accurate to
four decimal places.)
p-value =
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A0.05 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is different from 0.5. Assume that sample data consists of 45 girls in 81 births, so the sample statistic of n a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below. Click here to vie a. Identify the null hypothesis and the alternative hypothesis. Choose the correct...
A 0.05 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is greater than 0.5. Assume that sample data consists of 78 girls in 144 births, so the sample statistic of StartFraction 13 Over 24 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below. a. Identify the null hypothesis and the alternative hypothesis. b....
A 0.05 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is less than 0.5. Assume that sample data consists of 78 girls in 169 births, so the sample statistic of results in a z score that is 1 standard deviation below 0. Complete parts (a) through (h) below. Click here to view page 1 of the Normal table. Click here to view...
A 0.05 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is less than 0.5. Assume that sample data consists of 78 girls in 169 births, so the sample statistic of 6/13 results in a z score that is 1 standard deviation below 0. Complete parts (a) through (h) below. a. Identify the null hypothesis and the alternative hypothesis: b. What is the...
A multinomial experiment produced the following results:
(You may find it useful to reference the appropriate table:
chi-square table or F table)
Category
1
2
3
Frequency
117
100
83
a. Choose the appropriate alternative
hypothesis at H0: p1 =
0.50, p2 = 0.30, and p3 =
0.20.
All population proportions differ from their hypothesized
values.
At least one of the population proportions differs from its
hypothesized value.
b. Calculate the value of the test statistic.
(Round intermediate calculations to...