What must be the diameter of a hose if it is to deliver 8 liters of oil in 0.6 minutes with an exit velocity of 6 m/s?
here,
the volume of flow rate , V = 8/0.6 litre/min
V = 8/0.6 * (10^-3 /60) m^3 /s
V = 2.22 * 10^-4 m^3 /s
the exit velocity , v = 6 m/s
let the diameter of hose be d
V = Area * v
V = pi * (d/2)^2 * v
2.22 * 10^-4 = pi * ( d/2)^2 * 6
solving for d
d = 6.87 * 10^-3 m
the diameter of hose is 6.87 * 10^-3 m
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