Question

"Create a program in Python that converts a decimal to a hexadecimal, then from hexadecimal to decimal." I have completed the decimal-to-hexadecimal conversion, but how do I get the hexadecimal back to a decimal? Code please!

def decToHexa (n): # char array to store # hexadecimal number hexadeciNum = ['0'] * 100; # counter for hexadecimal # number array i = 0; while (n != 0): # temporary variable # to store remainder temp = 0; # storing remainder # in temp variable. temp = n % 16; # check if temp < 10 if (temp < 10): hexa DeciNum[i] = chr(temp + 48); i = i + 1; else: hexadeciNum[i] = chr (temp + 55); i = i + 1; n = int(n / 16); # printing hexadecimal number # array in reverse order j = i - 1; while (j >= 0): print ((hexadeciNum[j]), end = ""); j = j - 1; # Driver Code n = 2545; decToHexa (n);

Answer 1

If you have any doubts, please give me comment..

def decToHexa(n): 1. hexaDeciNum while(n#0): temp = 0 %3D temp = n % 16 if(temp<10): hexaDeciNum = chr(temp+48) + hexaDeciNum else: 8. hexaDeciNum = chr(temp+55) + hexaDeciNum n = int(n/16) 10 print(hexaDeciNum) 11 12 n = 2545 13 decToHexa(n) 14 15

15 16 def HexaToDec(hex): 17 18 hex[ :: -1].upper() hex = 19 20 for c in hex: 21 if c in "ABCDEF": 22 n += (ord(c) - ord('A')+10)*p 23 else: 24 n += (ord(c) - ord('0'))*p 25 26 p *= 16 print(n) 27 28 НехаТoDec("9F1") 29

nagarajuanagaraju-Vostro-3550:13012020$ python3 conversion.py 9F1 2545

Code:

def decToHexa(n):

hexaDeciNum = ""

while(n!=0):

temp = 0

temp = n % 16

if(temp<10):

hexaDeciNum = chr(temp+48) + hexaDeciNum

else:

hexaDeciNum = chr(temp+55) + hexaDeciNum

n = int(n/16)

print(hexaDeciNum)

n = 2545

decToHexa(n)

def HexaToDec(hex):

n = 0

hex = hex[::-1].upper()

p = 1

for c in hex:

if c in "ABCDEF":

n += (ord(c) - ord('A')+10)*p

else:

n += (ord(c) - ord('0'))*p

p *= 16

print(n)

HexaToDec("9F1")