8. The magnetic field shown in Figure P20.61 has a uniform magnitude of 25.0 mT directed...
3·The magnetic field shown in Figure 4 has a uniform magnitude of 25.0 mT directed into the paper. The initial diameter of the kink is 2.00 cm. (a) The wire is quickly pulled taut, and the kink shrinks to a diameter of zero in 50.0 ms. Determine the average voltage induced between endpoints A and B. Include the polarity. (b) Suppose the kink is undisturbed, but the magnetic field increases to 100 mT in 4.00 x10 s. Determine the average...
3. The magnetic field shown in Figure 4 has a uniform magnitude of 25.0 mT directed into the paper. The initial diameter of the kink is 2.00 em. (a) The wire is quickly pulled taut, and the kink shrinks to a diameter of zero in 50.0 ms. Determine the average voltage induced between endpoints A and B. Include the polarity. (b) Suppose the kink is undisturbed, but the magnetic field increases to 100 mT in 4.00 x 103 s. Determine...
magnetic field shown in Figure 4 has a uniform magnitude of 25.0 mT paper. The initial diameter of the kink is 2.00 cm. (a) The wire is 3. The directed into the quickly pulled taut, and the kink shrinks to a diameter of zero in 50.0 ms. Determine the average voltage induced between endpoints A and B. Include the polarity. (b) Suppose the kink is undisturbed, but the magnetic field increases to 100 mT in 4.00 x10" s. Determine the...
3. The magnetic field shown in Figure 4 has a uniform magnitude of 25.0 miT directed into the paper. The initial diameter of the kink is 2.00 em. (a) The wire s quickly pulled taut, and the kink shrinks to a diameter of zero in 50,.0 ms. Deen no the average voltage induced between endpoints A and B. Include the Suppose the kink is undisturbed, but the magnetic field increases y x103 s. Determine the during this period. (15) the...
3. The magnetic field shown in Figure 4 directed into the paper. The initial diameter quickly pulled taut, and the kink shrinks to f the kinkc is magnitude igure 4 the average voltage induced between endadiameter ofis 2.00cmde of 25.0 mT nk is undisturbed, but the magnetic field increases to a diameter of zero in 50.0 ms. Determine pulled a induced between endpoints 4 and B. Include the polarity. (b) mT in 4.00 the ki average voltage across terminals A...
4. A 2.00 C charged 1.00 g cork ball is suspended vertically on a 0.500 m long light string in the presence of a uniform downward-directed electric field of magnitude E-1.00x105 N/C. If the ball is displaced slightly from the vertical, it oscillates like a simple pendulum. (a) Determine the period of the ball's oscillation. (b) Should gravity be included in the calculation for part (a)? Explain. (15) 3. The magnetic field shown in Figure 4 directed into the paper....
The right edge of the circuit in the figure extends into a 50 mT uniform magnetic field.What are the magnitude and direction of the net force on the circuit?leftrightupdown
Magnetic field region There is a uniform magnetic field of magnitude B= 1.6T and directed out of the plane of the screen in the region shown. Outside this region the magnetic field is zero. A rectangular loop o.2 mby 0.6 m and of resistance 42 and mass 8 grams is being pulled into the magnetic field by an external force as shown. - What is the direction (CW or CCW) of the current induced in the loop? Calculate the magnitude...
An electron moves through a region with a uniform magnetic field of unknown magnitude directed in the +y direction At the instant that the electron is moving in the +z direction with a velocity of 2.86e6 m/s, it experiences a magnetic force of 1.24 pN in the +x direction. Calculate the magnitude of the magnetic field
An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.12 mT. If the speed of the election is 1.63 x 107 m/s determine the followi (a) the radius of the circular path cm (b) the time interval required to complete one revolution An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.12 mT. If the speed of the election is 1.63 x 107 m/s...