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A solution contains 1.31×10-2 M lead nitrate and 1.12×10-2 M iron(III) acetate. Solid potassium sulfide is...

A solution contains 1.31×10-2 M lead nitrate and 1.12×10-2 M iron(III) acetate.
Solid potassium sulfide is added slowly to this mixture.

What is the concentration of iron(III) ion when lead ion begins to precipitate?
[Fe3+] =  M

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Answer #1

2 31xIo (s-2210 2.29% lo 212 XID The concentoation Cs Scannéd with CamScanner

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