Question

For the fully-labeled PFD depicting a steady-state reactor above, which of the following would be a correctly written material balance for ethane (C_2 H_6)? n_1C2H6 = x_2C2H6 n_2 n_1C2H6 - n_CONSU, C2H6 = x_2C2H6 n_2 n_1C2H6 = x_2C2H6 n_1C2H6 - n_CONSU, C2H6 = x_2C2H6 + n_2 n_1C2H6 - n_CONSU, C2H6 = X_2C2H6

Answer 1

X2C2H6 X202 X2CO2 X2H20 X2N2 102 Reactor 2C2H6+702 → 4 CO2 + 6 H2O 1N2 For the fully-labeled PFD depicting a steady-state reactor above, which of the following would be a correctly written material balance for ethane (C2He)? 1C2H6 x2C2H6

we know that

accumulation = input + generation - output - consumption

in this case

input = n1C2H6

there is no generation

so

generation = 0

now

we know that

mole fraction = moles of component / total moles

moles of component = mole fraction x total moles

so

moles of C2H6 in output = XC2H6 x n2

so

output = X2C2H6 n2

comsumption = nconsu

now

at steady state

accumulation = 0

so

0 = n1C2H6 + 0 - ( X2C2H6 n2 ) - nconsu

n1C2H6 - nconsu = X2C2H6 n2

so

the answer is option 2) n1C2H6 - nconsu = X2C2H6 n2