Homework Answers
a)
PE = mgh = 2m gh
====
b)
using 3rd equation of motion
u^2 = 2 g h
u = sqrt ( 2gh)
====
c)
using conservation of momentum
m1 u1 + m2 u2 = (m1 + m2) v
2 m sqrt(2 gh) = (3m) v
v = (2/3) sqrt ( 2gh)
======
d).
final velocity of m1
v1 =( m1 - m2) u1 / ( m1 + m2)
v1 = m sqrt (2 gh) / 3m
v1 = sqrt(2gh) / 3
final velocity of m2
v2 = 2 m1 u1 / ( m1 + m2)
v2 = (4/3) sqrt(2 gh)
======
Comment in case any doubt, will reply for sure.. Goodluck
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