Question

I am having trouble with this. I did an experiment in physics and was asked to figure out what ? is using this formula T=2$\pi$Square root $\alpha$(l/g). THe length is 38 cm but where does $\alpha$come into play and how do I figure it out? I do have data. Please help   This is for a rod pendulum

Answer 1

Answer 2

this is just to calculate TIME PERIOD OF A SIMPLE PENDULUM UNDER SHM where L be the length of pendlm and g be the gravitational force

his equation is valid for a swinging pendulum of negligible string weight and swing angle of less than 5deg, where T is the period of 1 full swing, L is length of pendulum and G is gravitational acceleration

Answer 3

Answer 4

Using the experimental data you can get 'alpha'.

Let me elaborate.

Lets say you have n sets of data for T, say T1, T2, T3......Tn.

Similarly n sets of data for length(l) or gravity(g).

So you can use averaging to find out T from this:

T_avg=(T1+T2+.....Tn)/n

Similarly for l and g also.

Now using the given relation you can easily find out 'alpha'

Answer 5

Answer 6

in this case of rod pendulum.

A rigid uniform rod of length L pivoted about either end has moment of inertia I = (1/3)mL².

The center of mass is located at the center of the rod, so R = L/2.

Substituting these values into the above equation gives

T = 2??2L/3g.

This shows that a rigid rod pendulum has the same period as a simple pendulum of 2/3 its length.

Also here alpha is 2/3