Question

Problem One: a) A signal 10 whose amplitude spectral density F(m) is shown below is sampled using a periodic rectangular pulse waveforms of width 15 msec, and of period equal to the Nyquist interval. Sketch the magnitude spectral density of the sampled signal from 0 to 100 it rad. labeling all the important points. F(0) -24 247 16 marks]

Answer 1

I let ces assume a lectangulal pulss train. . +The -To fourier mansform of a rectangedal periodic signaler pla E coneincest fet, Xple) = { oncnolw-news) (n = AT Sire fino Ton] =24 NA i opite faire consta de mai sus. s yped fina pisarne un ar lances) here for pulse T= ismser. ; nyquist interval= 2 fm Horw -Ź_991028) Binc (nga] luminoso nu har spec. c 02 = Qynz. wyne owo) CS Scanned with CamScanner 0-36

Cod -21 Xprw = 20 927 Sise [noac 6l6o-usa) IT ufa tafw) f(c) = the -Qux 241 of shifted to the location after Sampling signal will be impulses, * we are interested in sampling from - look to 10 - Sinca= sinad 0.921 fioc (0.36n) = Simo 36117072 0,3670 піс = 2 810 0.367n an Sin co.36n = fimo 3670 0-3610 at no 2.72ABIRACO:36n) - (0-361) COS0.36an 2 fino.3649 Xplw) – 26903670 nes n using litt reele 2 fino-36Tn_saro - Hospinal rule differennahing u no ) 0.726 816-uer) denarinatol. numeroctol . i Xpreo) 10.782.86 ali 0.8. q 966 UST -484 +241 246 Scanned with CamScanner

Xples = É Q600269N 010.wen) is ee n naan = 0.721 + 88i90.367 816-487) + 2 sin(-0.361) 8 (64468) no +7 870.721 h 016-964) + asin(-0.728) SIW+967). = 0.726+ 1.8 816-487) +18F(co+u89)+ 0.8 0110-96A) +0.8 SC6+964) I pAlco) -241 DUT A +485 -961 960 487 2x9.96-5.58 vokal 6 anted / 18 ca Eliminated Eliminated W her USA o taut 720 967 1200 -auk no 1967 -721 ust 71001 -1001 sampled signal from oto 100% Magnitude spectal density of 15.52 Scanned with Camif positive 241 frequencies only 487 92 967 Considued look