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[Refer Given the following equilibrium constants at 425°C, 1 Na2O(s) – 2 Na(1) +02(9) K= 5 x 10-25 NaO(9) = Na(1)+ - 02(9) K2
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Solution : cas Nao (s) +2 O2(g) → noga (5) Napol) = erald) +5 og 11) naoz (5) gwald) toz - reverse the eqn 02 + gevalle) = NaK, х К.- Ка : 581025 x 201005 8 % 1029. TO 10-30 E = x10-23 - You - 12.50 © 9 vа ela) = ra, O, 4) Nao (g) - wald) + / O (9) -

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