Question

ONLY NEED E,F,G

Wrong answer/ Already tried

E= -17.36 is wrong

F= 1.49 is wrong

G= 0.5 is wrong

Correct Answers Below

A= Real

B= -0.31

C=9.84

D= Real

(8%) Problem 12: Consider the compound optical system shown in the diagram, where two thin lenses of focal lengths 75 cm (left lens) and 40.5 cm (right lens) are separated by a distance 21 cm Otheexpertta.com If an object is placed a distance do >fi to the left of the first lens (the left lens), will the resulting image from the first lens be 13% Part (a) real or virtual, and inverted or upright? 13% Part (b) If a 2.9 cm tall object is placed as indicated in part (a), and the image formed is 0.89 cm tall, what is the magnification of the first lens? 13% Part (c) Using the information from part (b), calculate the image distance, in centimeters, from the first lens 13% Part (d) Does the image formed by the first lens serve as a real or a virtual object for the second lens? 13% Part (e) What is the image distance, in centimeters, for the second lens? 13% Part (f What is the magnification of the second lens? Grade Summary M2 1.49 0% Deductions Potential 100 %e 8 9 HOME Submissions cos0 14 Attempts remaining: cotano as acos0 A 4 5 6 0% per attempt) detailed view 1 2 3 atano acotan( si 0% cosh0 tanho cotanh0 VO Degrees O Radians BACKSPACE DEL CLEAR Submit Hints: 5% deduction per hint. Hints remaining: 1 Feedback: 5% deduction per feedback. 13% Part g What is the total magnification of this compound optical system?

Answer 1

(e) do2 = 21 - 9.84 = 11.16 cm

f2 = 40.5 cm

Applying 1/f = 1/do + 1/di

1/40.5 = 1/11.16 + 1/di2

di2 = -15.4 cm

So image distance = 15.4 cm left to the second lens.

(F) m2 = - di2 / do2 = - (-15.4) / (11.16)

= 1.38

(g) M = m1 m2

= (-0.31)(1.38)

= -0.43