Question

please help, I don't

The fraction defective of automotive pistons made by the Precision Piston Co. is given in the worksheet the worksheet C07DataInsRsv.xlsx for Prob. 7-5 for 25 samples. One hundred units are inspected each day. Construct a p-chart and interpret the results. Problem 7-5-Instructor Reserve Precision Piston Company Sample Value Avoo oo Oo oo co woo o 7

know how to approach this problem anymore since i'm not getting the correct p-value and lcl,ucl. due to covid im sitting in front of my computer all day, so you can count on to instantly thumbs up

Answer 1

loo 10.08 0 NJ 000 60 = = 0 V 3 16 17 (00 10.08 1oo 0.16 P = total no defective 0.08 a total no sampled 100 0.07 100 10.04 P = 239 -0.0956 25oo 100 0.08 100/0.13 Control limits for p chart 1000.06 1000 og UCL= È +3 | P a 1000.11 1090.19 LCL = -3/Ď å logo.nl 10 10.08 1000.03 J = 1-P. Too 0.08 ñ- average of sample sizes 1ooo.10 å=1-0.ogs6 = 0.9044 1000.14 ñ = 100 1oo10.07 ooong JC L=0.0956t3/(0.0956) (0.9044) 1000:13 1000.15 = 0.0956+3 / 0.0008 64 6064 1006.06 1006.07 -0.0956 +0.08 82125106 1000.11 = 0.18381257). 2500 I = 0.1838 I LCL = 0.0956-3/(0.0956) Co.g044) V 100 = 0.0956-0.0882125706 -0.007387 0.0074 Cl = p = 0.0956 19 7 20 21 13 Too 22 23 IS 6 7 1 239 25 E

- 會」會自Dota lep S? | 世區屬會員贈電感|一生一喜。」 GBP Chart of d P Chart of d 1.20 UCL=0.1838 0.15 Proportion A.10. P=0.0956 CS C10 C111 C2 C13 LCL=0.0074 10.00 s it 13 15 17 19 21 23 25 Sample 100 100 24 25 100 100 合 2020-4-18 09:05 回 Sheet