Question

An electrolytic cell is set up. Two inert electrodes are attached to an external 6V battery, and are placed into a solution. The solution is a 1.00 M aqueous solution of calcium iodide (CaI2 (aq)). Determine which half-reactions are happening at the cathode and the anode of the electrolytic cell and explain your answer.

My teacher uses half reaction with water to solve but I don't understand how you chose which water half reaction to use since there are three of them

They use 2 H2O (l) + 2 e- ---> H2 (g) + 2 OH- (aq) Enot = -0.83 V

for the reduction reaction

For the oxidation reaction they use: 2H2O (l) ----> O2 (g) + 4 H+ (aq) + 4e- Enot = -1.23 V

Please explain why

Answer 1

electrons anste henetom 걔 0,0 ,002

- 2 to 0 Yeduced About Anode & Ca thode CATHODE i e elechode where Reut Caba, place

Corre cell reaetun 2/々o@t 2e →beHa» er) ove yon reed me