Question

13. What is the equation (molecular or net ionic) for the reaction that take place when NaOH is added to the buffer solution in the question above (#12)? Use exact, not generic, formulas.

need help on question 13

Answer 1

When, NaOH is added to benzoic acid and sodium benzoate buffer solution,

the NaOH reacts with benzoic acid to give sodium benzoate. Thus, the concentration of sodium benzoate increases and concentration of benzoic acid decreases in the buffer solution.

C6H5COOH(aq) + NaOH(aq) ----------------> C6H5COONa(aq) + H2O(l) [Molecular equation]

C6H5COO-(aq) + H+(aq) + Na+(aq) + OH-(aq) ----------------> C6H5COO-(aq) + Na+(aq) + H2O(l) [Complete ionic equation]

H+(aq) + OH-(aq) ----------------> H2O(l) [Net ionic equation]