formula to convert bits into second = bitTimes/Bandwidth (in Bps) seconds
a) A will detect collision at time = propagation delay/2 = 240/2 = 120 bit times =120/4.8*10^6= 25 microseconds (using formula)
b)
since passive medium i.e. ethernet bus cannot detect collision . Active devices i.e. sender and receiver can only detect it.
The collision will be detected after time = 2*propagation delay
+ transmission delay in jam signal
= 2*240 + 48 bit times = 528 bit times = 110 microseconds
after time t=110 microsecond bus will be idle for 96 bit times
C)
after sensing this collison, since A has choosen KA=0.
A will start retransmission after sensing bus for 96 bit times or 20 microsecond after collision detection
so at t = 110 + 20 = 130 microsecond A willl start retransmission
D)
frame transmission time by A = transmission delay + propagation delay
since the frame size = 1200 bits
so transmission delay = 1200/4.8*10^6 = 250 microseconds
time taken by A to sucessfully transmit the frame to B = 250 + 50= 300 microseconds
hence at t = 130 + 300 = 430 microseconds B will recieve all bits of frame successfully.
7. (4 pointa) Cossider two nodes A and B consected vis an Etheret bo of 48Mbps...
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