Question

A rectangular loop of wire is placed midway between two long straight parallel conductors as shown. The conductors initially carry currents I1

I

1

and I2

I

2

as indicated. Both currents can be assumed to be positive (i.e. conventional currents initially flow in the directions as depicted in the figure). If current I1

I

1

is decreasing at a constant rate given by dI1dt

d

I

1

d

t

= -1.0 mA/s and I2

I

2

is constant, then the induced current in the loop is:

A rectangular loop of wire is placed midway between two long straight parallel conductors as shown. The conductors initially carry currents I, and I, as indicated. Both currents can be assumed to be positive (i.e. conventional currents initially flow in the directions as depicted in the figure). If current I, is decreasing at a constant rate given by --10 mA/s and 12 is constant, then the induced current in the loop is:

Answer 1

from the fleming left hand rule

current i1 produces a magnetic field is directed into the page,and current i2 produces a magnetic field which is directed out of the page.

the total flux depends on the currents due to i1 and i2

when current i1 is decreasing and i2 is constant

that is i1 is less than the i2 , according to Lenz's law the direction of induced current is counter clock wise direction

here net flux is decreasing