Question

pls show work

2. Find the effective moment of inertia for the following concrete sections (f. = 4000 psi) when cracked moment to applied moment ratio is (a) 0.9 (b) 0.7 and (c) 0.5. Note: values are not from an actual beam. Calculate the applied moment if the beam span is 8 ft and (a) the central point load is 8 kip and (b) a UDL of 1 kip/ft is applied. Calculate the deflection due to a point load of 8 kip for the span of 8 ft on this concrete beam with (f' = 4000 psi), where the cracked moment to applied moment ratio is 0.7 bxD Id f = 7.5/fo Igross bD3 Neutral axis depth from top (c)(in.) | 1g = Mer = f 2 12 Mer = f the (in xin.) (in) (psi) (in.) (lb-in) (k-ft) 12x27 5.6

Answer 1

Answer - According to collect from the data → let us assume that the equations are - Now we have to consider that the data as followed - To findout the effective moment of inferia for the conan- trece sections (fc = u ooopsi) for the moment of applied ratio is -> d=24, p . 56. ys 7517 ? 56. ye 75C a= 0.045 А в. QE AAVA – AB VB ADVA 0.918 misec YA = 9 0 .045 o.ous VB= 0.us 0-785x(0.357 → 0.468 mlsee 0.45 Tllu x(0-3532 7 La 0.45 o.us 70.358 m/sec . ly x. (0.4% 0.785 80.16 → Now we have to applying the bernolies equatio Pet you +2A = + + 2B the 28 tones .. let us the major uflur 1. hf= 290

Now we have to applying the values are 50+ 0-919) to $B +10:468) 120+ MX 0.02X ISDOX00.919) 249.81 eg , 249.81 2x908180.25 t :P 10 i 50 + 0.814 19.62 0.219 1962 0:08 X 1500-X0.840 19.62x0.25 → 50+ 0 bu?+10 = dos 70. olll +10+ 120 x eo . > 60.002 - 0 11 +20+20.55 5 song = 19.46m. → let us the applying for bernokies equations are A&D learn remain +2A = Sten +20 the Chea the othfo) 50+ 0.912) H10 - Set (0.158) + 4D + 4x 4X0-02 x/500 0.913 ax981 249.81 2 x 9.81.X 025 UX003 *1200 +0.4682 + 2 X 9081 X0-35 UX0.04 X2000 X 0.03582 2 x 9.87X0.4 - 50+ 0.0421-0 = 9. OGS+40 + 1008 4.905 +302.4, + 6.867 401.6 7. GOL ny = -10.315 m.