Question

Name Section Useful formulas w=fF.di, Ww=AE" E=U+K+ Ermal U=Uc+Uspring K. Uab) = mgy, Urning (w) = 366 – soba F =- Fa = -mg, Fpring = -ky-yo) h 1.) A kid of mass m is momentarily at rest, and then drops onto a trampoline from a heighth above the surface. The acoderation due to gravity has magnitude y. Assume no dissipative forces exist. Assume the trampoline behaves like a spring with spring constant k a.) What is the kid's speed the moment they first come into contact with the flat trampoline surface? (cottimed on other side)

Answer 1

a Applying conservation of energy High = Ź mu? il va agh so, the kid's speed the moment they first come into contact with the hat trampoline surface Sagh - Applying conservation of total energy of the system, mg 1h+d) = 1/2 k d² Kd² = 2 ngintd) K = 2mg (htd) d2 So, Let the kids would Hy a distance he above the un-stretched surface of the trampoline. By conservation of Energy: ng (h+d) = { kd²+ W ing (htd) = Main+d) + W 1 mg h' = mght W mgh tw ng hi ng is = ht ฟ CS$canned with CamScanner

(d). Yes, the total energy of the kid-Earth-trampoline system changed because the kid did some external work on the system by changing his muscular energy into work.