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Weight of 5-mL conical vial weight of 5-mL concia
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4. Weight of bromobenzene –

Given-

Weight of 5ml conical viol = 23.148g

Weight of 5ml conical viol and bromobenzene= 24.163g

Weight of bromobenzene = 24.163g - 23.146g = 1.015g

5. Calculate the theoretical yield of triphenylmethanol.

Weight of triphenylmethanol = 0.759g

The molar mass of Ph3COH is 260.3 g/mol.

So of moles Ph3COH = Weight of triphenylmethanol/ the molar mass triphenylmethanol

                                       = 0.759g /260.3 g/mol = 0.0029 moles

Theoretical yield=0.0029 mol Ph₃COH × 260.3 g Ph3COH/1mol Ph₃COH= 0.759 g Ph3COH

7- Equation for reaction between-

(a.) Bromobenzene and magnesium

C6H5Br + Mg -----→ C6H5MgBr

(b) Phenylmagnesium bromide and benzophenone

(C6H5)2C=O + C6H5MgBr--------→ (C6H5)3COMgBr

(c)Product of b and acid

(C6H5)3COMgBr + H+------→ (C6H5)3COH + Mg2++ Br

8 (a)

In the process of producing triphenylmethanol, some side products have been produced at the same time such as biphenyl.

C6H5MgBr +C6H5Br ---------->(C6H5)2

(b)The ether layer was concentrated over a steam bath at 60-80 °C until the triphenylmethanol was formed.

(c) Petroleum ether is used in the experiment in order to let the biphenyl dissolved in it so that this side product can be removed via recrystallization. Due to the higher polarity of the triphenylmethanol compared to biphenyl, the triphenylmethanol dissolve easily in the polar methyl petroleum ether.

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