Question

Q1. Use MATLAB to calculate sum of the AC voltages. Plot all three voltages in the same figure using the inbuilt function subplot(). The frequency of the signal is 10 Hz. Vary the time, t, so that you can view few cycles of the AC voltage. vi(t) = 10 V sin(wt +T/2) vz(t) =15 V sin(wt+1/3) vs(t) = (t) + v2(t) Q2. Use voltage vi(t) from Q1 and impedance, Z = 50 L 30°, and find phasor current I, then express current as function of time, i(t). Plot vi(t) and i(t) using plot() function. What is the phase difference between the voltage and current?

Answer Q2

Answer 1

02. 4, (+) = 10 sin ( wt + 7/2) Volts. considering V, (+) to be the reference, it can be written as = 1 LOO v lin phasor form) where 10 is the rimis value of voltage V,. Now, the impedance => 5230°... Thus, current in phasor form, | IEO LO 12 -30' Amp. 5 L 30 Thus, in time domain it is represented as i(t) = √2 xr2 sin (wt + Tl2 - 7/6) => Tilt) = 2 sin (wt + T/3)] Amp. => Phase Difference: Current is lagging the voltage by 30.

Command Window >> t=[0:0.0001:1]; vl=10*sin (2*pi*10*t+pi/2); 11=2*sin (2*10*pi*t+pi/3); plot(t,11,t, vl) fx >>

LITT 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9