The molecular weight of the Al2(SO4)2 =342.15 gm/mol
Molarity of Al2(SO4)2 =
M = (1.06 * 1000) / (342.15 * 250) = 0.01239 moles
A solution of Al2(SO4)2 generate a 2 moles Al3+ of and 3 moles of SO4--
therefor a molarity of the Al3+ ion =
M (Al3+) = 0.01239 * 2 = 0.02478 moles
Molarity of stock solution of Al3+ = 0.02478 moles
The molecular weight of the KIO3 =214.001 gm/mol
Molarity of KIO3 =
a quantity of solute KIO3 is 5.86 mole
therefor total quantity is = 5.86 * 214.001 = 1254.04 gm
and volume of solution 2.80 L = 2800 ml
then calculate the
M = (1254.04 * 1000) / (214.01 * 2800) = 2.0927 moles
Molarity of stock solution of KIO3 = 2.0927 moles
Molarity of dilute solution of KIO3 =
calcualting using below formula
M1 * V1 = M2 * V2
M1= Initial molarity = 2.0927
V1 = Initial Volume = 10 ml
M2 = Final Molarity = ?
V2 = Final volume = 100 ml
therefor M2 = (M1 * V1)/ V2
M2 = ( 2.0927 * 10 ) / 100
M2 = 0.20927 mole
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