here,
the cross sectional area , A0 = 0.0075 m^2
v0 = 1.3 m/s
the new transaltional speed be v
the new cross sectional area , A = 0.0033 m^2
using equation of continuity
A0 * v0 = A * v
0.0075 * 1.3 = 0.0033 * v
solving for v
v = 2.95 m/s
the new speed is 2.95 m/s
end . is the r than, ithin 44. Calculate Water flows with a speed of 1.3...
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