we know that
work done = change in potential energy
W = 1.5x^2 + 4x ( from x = 2 to x = 3)
W = 11.5J
The conservative force F = (3.00x + 4.00) N does work on a particle moving along...
A 4-kg particle moves along the x-axis under the influence of a conservative force. The potential energy is given by U(x) = bx^3 , where b = 8.0 J/m^3 . What is the magnitude of the acceleration of the particle (in m/s2 ) when it is at the point x = 2 m?
A conservative force F(x) acts on a 2.0 kg particle that moves along an x axis. The potential energy U(x) associated with F(x) is graphed in the figure. When the particle is at x-2.0 m, its velocity is -1.4 m/s. (a) What is F(x) at this position, including sign? Between what positions on the (b) left and (c) right does the particle move? (d) what is its particle's speed at x = 7.0 m? x (m) 10 15 (a) Number...
A conservative force F(x) acts on a 1.7 kg particle that moves along an x axis. The potential energy U(x) associated with F(x) is graphed in the figure. When the particle is atx-2.0 m, its velocity is -1.7 m/s. (a) What is F(x) at this position, including sign? Between what positions on the (b) left and (c) right does the particle move? (d) what is its particle's speed at x = 7.0 m? x (m) 0 10 15 0 -5...
A single conservative force acts on a 4.50-kg particle within a system due to its interaction with the rest of the system. The equation Fx = 2x + 4 describes the force, where Fx is in newtons and x is in meters. As the particle moves along the x axis from x = 1.10 m to x = 6.55 m, calculate the following. (a) the work done by this force on the particle J (b) the change in the potential...
A particle of mass m = 2.70 kg moving along the x axis from x = 0 to x = 10.6 m experiences a net conservative force in an isolated system given by F = 5x − 4, where F is in newtons and x is in meters. (a) What is the work done on the particle by the force F? J (b) What is the change in the potential energy of the system during this motion? J (c) If...
A force parallel to the x-axis acts on a particle moving along the x-axis. This force produces potential energy U(x) given by U(x) = αx4 , where α = 1.25 J/m4. What is the force (magnitude and direction) when the particle is at x = -0.856 m?
Chapter 08, Problem 077 A conservative force F(x) acts on a 1.7 kg particle that moves along an x axis. The potential energy u(x) associated with F(x) is graphed in the figure. When the particle is at x = 2.0 m, its velocity is -1.9 m/s. (a) What is F(x) at this position, including sign? Between what positions on the (b) left and (c) right does the particle move? (d) What is its particle's speed at x = 7.0 m?...
Particle of mass m moves along x-axis under a conservative force given by F=A(e^(-2(x-xo)/xo)-e^(-x/xo)) where A and xo are constants. Assume potential energy at infinity (Uo) =0. Calculate the potential energy of the particle in term of A,x,and xo.
A single conservative force F = (5.0x - 11)i N, where x is in meters, acts on a particle moving along an x axis. The potential energy U associated with this force is assigned a value of 25 J at x = 0. (a) What is the maximum positive potential energy? At what (b) negative value and (c) positive value of x is the potential energy equal to zero?
A single conservative force F = (5.0x - 11)î N, where x is in meters, acts on a particle moving along an x axis. The potential energy U associated with this force is assigned a value of 24 J at x = 0. (a) What is the maximum positive potential energy? At what (b) negative value and (c) positive value of x is the potential energy equal to zero? with s.i units