Question

Due Wed Feb 12th 5:00 PM For all problems, unless otherwise stated, use the following values for blood: Density = 1060 kg/m3 and viscosity = 0.0035 Pa-s

Answer 1

Given Data: diameter d = 10 mm Length L = 50 mm Temsile force p= 20 kN = 204103 N change in length AL=0.12 mm change in diameter ad= 0.0083 mm ay change in length is given by . DL= ALE Shte AE where, A = cross sectional airea - ģxo? A = 4 x 10²= 78.539 mm² E = young's modulus of elasticity ( Elastic modulus of material) 200103 x 50 012 - 78-539x E E = 106104-39 N/mm2

IE= 106104.39 mpal TE= 106.104 apa is 106.104 apa - Elastic modulus of material by Poisson's ratio poisson (M), Lateral strain . Longitutional streen 0-0083 Ad - 0.00083 sprein =- lo Lateral lateral stenine A4 - 00083 Longitucional struin o - 012 000083 = 0.0024 So - = n = 0.345 ps o 0.345 0.00083 0-0024 TM= 0.345 ratio is 0.345 The poisson's