PLEASE SHOW WORK AND PLEASE DON'T GET IT WRONG THIS TIME!!! 1. A 1940 kg car...

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Question

PLEASE SHOW WORK AND PLEASE DON'T GET IT WRONG THIS TIME!!!

1. Image for A 1940 kg car moving at 20.0 m/s collides and locks together with a 1540 kg car at rest at a stop sign. Show t

Answer 1

Answer #1

$m_1=1940\: kg,m_2=1540\: kg,v_1=20\: m/s$

$v_{f1}=\frac {m_1-m_2}{m_1+m_2}v_1= 2.29885\: m/s$ (Final velocity of the moving car in laboratory frame)

$v_{f2}=\frac {2m_1}{m_1+m_2}v_1= 22.29885\: m/s$ (Final velocity of the rest car in laboratory frame)

$v_1'=(20-10)\: m/s =10\: m/s$ (Initial velocity of the moving car in the moving reference frame)

$v_2 '=-10\:m/s$ (Initial velocity of the rest car in the moving reference frame)

P_i=m_1v_1'+m_2v_2'

$P_i=(1940\cdot 10 -1540\cdot 10)\: kgm/s = 4000\: kgm/s$ (Initial momentum)

$v_1''=v_{f1}-10=-7.70115\: m/s$ (Final velocity of the moving car in the moving reference frame)

$v_2''=v_{f2}-10=12.29885\: m/s$ (Final velocity of the rest car in the moving reference frame)

P_f=m_1v_1''+m_2v_2''

$P_f=3999.99\approx 4000\: kgm/s$ (Final momentum)

So it's conserved in the reference frame.

Answer 2

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