Consider the initial value problem y'' + 2y' – 15y = 0, y0) = a, y'0...
Consider the initial value problem y'' – 2y' – 8y = 0, y(0) = a, y'(0) = 6 Find the value of a so that the solution to the initial value problem approaches zero as t + oo Q = a =
21. Solve the initial value problem y" - y-2y= 0, y(0) = a , y ( 0) the solution approaches zero as t 0o. 2. Then find a so that
Consider the initial value problem y'' + y' – 12y = 0, y(0) = a, y'(0) = 5 Find the value of a so that the solution to the initial value problem approaches zero ast → a = Preview
Solve 2y'' – 5y' – 25y = 0, y(0) = -6, y'(0) = – 15 (t) = Consider the initial value problem y' + 3y' – 10y = 0, y(0) = a, y'(0) = 3 Find the value of a so that the solution to the initial value problem approaches zero as t + oo a = 1
please show all steps , thank you 6. Consider the initial value problem y" + 2y' + 2y = (t – 7); y(0) = 0, y'(0) = 1. a. Find the solution to the initial value problem. (10 points) b. Sketch a plot of the solution for t E (0,37]. (5 points) c. Describe the behavior of the solution. How is this system damped? (5 points)
(5 points) Consider the following initial value problem: Y" - 2y - 35y = sin(4t) y(0) = 3, y'(0) = -4 Using Y for the Laplace transform of y(t), i.e., Y = L{y(t)}, find the equation you get by taking the Laplace transform of the differential equation and solve for Y(S) = (35+2)/(s^2-25-35)+4/((s^2-28-35)*(s^2+16))
Consider the initial value problem for function y given by, Consider the initial value problem for function y given by, (a) Find the Laplace Transform of the source function, F(s) = L[-3 F(s) = (b) Find the Laplace Transform of the solution, Y(s) Lt) Y(s) - (c) Find the solution y(t) of the initial value problem above. s(t) Recall: If needed, the step function at c is denoted as u(t - c) -1] Help Entering Answers Preview My Anawers Submit...
Solve y"' + 4y = 0, v(©) = 1, v" ) = -2 s(t) = Preview Get help: Video Points possible: 2 Unlimited attempts. Submit
consider the initial value problem. y"+5/6y=1-1/5t , y(0)=Y0
The polynomial of degree 3, P(x), has a root of multiplicity 2 at5 and a root of multiplicity 1 at z3. The y- intercept is y37.5. Find a formula for P(z). P(x)- Preview Get help: Videc License Points possible: 1 Unlimited attempts. Submit Write an equation for the polynomial graphed below -2 -3 y(x)- Preview Get help: Video Points possible: 1 Unlimited attempts. Submit Search or type URL calculus Section 22 Spring 2019> Assessment Write an equation for the polynomial...