Question

15, 17, 14, 16, 12, 9, 19, 10, 13, 11 First: Create an iterative distribution table...

15, 17, 14, 16, 12, 9, 19, 10, 13, 11

First: Create an iterative distribution table consisting of 4 categories, then distribute the data on this table.

Second: Calculate the cumulative iterations of the iterative distribution schedule.

Third: Calculate the relative frequencies and the cumulative relative frequencies.

Fourth: If we consider that the student who received less than 12 deposits, calculate the percentage of successful students.

Fifth: Calculate the arithmetic mean from the iterative distribution schedule that you created in the first application.

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Answer #1

Arrangement of data in smallest to largest: 9,10,11,12,13,14,15,16,17 and 19.

First: Creation of an iterative distribution table consisting of 4 categories with distributing the data on this table.

Group Class Frequency
1 8 11 2
2 11 14 3
3 14 17 3
4 17 20 2

Second: Calculate the cumulative iterations of the iterative distribution schedule.

Group Class Frequency cumulative iteration
1 8 11 2 2
2 11 14 3 5
3 14 17 3 8
4 17 20 2 10

Third: Calculate the relative frequencies and the cumulative relative frequencies.

Group Class Frequency (F) cumulative iteration (CF) relative frequencies=F/10 cumulative relative frequencies=CF/10
1 8 11 2 2 0.2 0.2
2 11 14 3 5 0.3 0.5
3 14 17 3 8 0.3 0.8
4 17 20 2 10 0.2 1
Total 10

Fourth: If we consider that the student who received less than 12 deposits, calculate the percentage of successful students.

Ans: Successful students are the students who 12 or more than 12 deposits.

So, the percentage of successful students=(6/10)*100%=60%.

Fifth: Calculate the arithmetic mean from the iterative distribution schedule that you created in the first application.

Group Class Frequency (F) mid-value (x)=(Upper limit+lower limit)/2 Fx
1 8 11 2 9.5 19
2 11 14 3 12.5 37.5
3 14 17 3 15.5 46.5
4 17 20 2 18.5 37
10 140

The arithmetic mean from the iterative distribution schedule=140/10=14

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