15, 17, 14, 16, 12, 9, 19, 10, 13, 11
First: Create an iterative distribution table consisting of 4 categories, then distribute the data on this table.
Second: Calculate the cumulative iterations of the iterative distribution schedule.
Third: Calculate the relative frequencies and the cumulative relative frequencies.
Fourth: If we consider that the student who received less than 12 deposits, calculate the percentage of successful students.
Fifth: Calculate the arithmetic mean from the iterative distribution schedule that you created in the first application.
Arrangement of data in smallest to largest: 9,10,11,12,13,14,15,16,17 and 19.
First: Creation of an iterative distribution table consisting of 4 categories with distributing the data on this table.
Group | Class | Frequency | |
1 | 8 | 11 | 2 |
2 | 11 | 14 | 3 |
3 | 14 | 17 | 3 |
4 | 17 | 20 | 2 |
Second: Calculate the cumulative iterations of the iterative distribution schedule.
Group | Class | Frequency | cumulative iteration | |
1 | 8 | 11 | 2 | 2 |
2 | 11 | 14 | 3 | 5 |
3 | 14 | 17 | 3 | 8 |
4 | 17 | 20 | 2 | 10 |
Third: Calculate the relative frequencies and the cumulative relative frequencies.
Group | Class | Frequency (F) | cumulative iteration (CF) | relative frequencies=F/10 | cumulative relative frequencies=CF/10 | |
1 | 8 | 11 | 2 | 2 | 0.2 | 0.2 |
2 | 11 | 14 | 3 | 5 | 0.3 | 0.5 |
3 | 14 | 17 | 3 | 8 | 0.3 | 0.8 |
4 | 17 | 20 | 2 | 10 | 0.2 | 1 |
Total | 10 |
Fourth: If we consider that the student who received less than 12 deposits, calculate the percentage of successful students.
Ans: Successful students are the students who 12 or more than 12 deposits.
So, the percentage of successful students=(6/10)*100%=60%.
Fifth: Calculate the arithmetic mean from the iterative distribution schedule that you created in the first application.
Group | Class | Frequency (F) | mid-value (x)=(Upper limit+lower limit)/2 | Fx | |
1 | 8 | 11 | 2 | 9.5 | 19 |
2 | 11 | 14 | 3 | 12.5 | 37.5 |
3 | 14 | 17 | 3 | 15.5 | 46.5 |
4 | 17 | 20 | 2 | 18.5 | 37 |
10 | 140 |
The arithmetic mean from the iterative distribution schedule=140/10=14
15, 17, 14, 16, 12, 9, 19, 10, 13, 11 First: Create an iterative distribution table...
7 8 9 10 11 12 13 14 15 16 17 18 19 20 ) The human heart is found in which location? 10 Between the right midclavicular line and the right border of the sternum and below the clavicle to the eighth rib 20 Between the second and the fifth intercostal spaces from the right edge of the sternum to the loft midclavicular line 30 Between the third and sixth intercostal spaces from the left midclavicular line to the...
using matlab
Create the following matrix B. [18 17 16 15 14 13] 12 11 10 9 8 7 6 5 4 3 2 1 Use the matrix B to: (a) Create a six-element column vector named va that contains the elements of the second and fifth columns of B. (6) Create a seven-element column vector named vb that contains elements 3 through 6 of the third row of B and the elements of the second column of B. Create...