Question

The solid substance that is collected dried and weighed is Cu(s). 6) What is the mass of Cu(s) collected? (Report in grams using all digits shown).(0.5 points) Cu 9 7) What is the theoretical yield of Cu(s)? (Report in grams using 4 significant figures) (2 points) 1.389 8) What is the percent yield of Cu(s)?(1.5 points) 9) What errors (list at least 2) could lead to less than 100% yield?(2 points) Think about the final weighing and transfer of product that was shown in the video. 10) Considering the final weighing and sample transfer suggest an alternative method that the experimenters may have used to improve the percent yield.(2points)

Answer 1

- 2 249.591 - 2 1.222 Fe (s) + cusog (aq) + Cu(s) + Fesos (09) 1. Mass of cus04:5 H20 weighed-out 7.845g 2. No. of moles of cusO4.5H20 7(7.845 = 3:145x10 3. Mass of Fe weighed-out - 1.222 g 4. No. of moles of Fe 5. I mol. Fe Imol. Cusoa. Hence, Fe is the limiting reactant 6. Mass of cus) collected = 1.389 g 7. Theoretical yield of cue = 2.188 xlö ? mol. = 63.546x2.188x10 S. Percent (:389 x 100) % 99.90% 55.845) = 2.188710 = 1.390 g yield of ce 1.390