Question

clo0 Molor Mass of water 18gmol 0.90849 009 146 - 0:00516 mole 0.0958g - 0.0053amole 188 0,00586mol 5.86X103mol/g 0,00SIomal 0,0 Complete the following table. Show sample calculations for * and ** on next page. [3 pts] 6. Table 11-7 Calculation of Stoichiometric Mole Ratios within the Unknown Compound C20,2- Fen+ K* H20 Moles of component per one gram of compound Mass of component per Fes 1.007 one gram of compound All moles divided by the lowest number of moles Whole number ratio Dec. 3, 2019 by Sheppard Exp 11 Page 9

Answer 1

Based on your given information and data :

Average Moles of Components per gram of compound :

• H₂O : 0.00593 mol/g
• Oxalate (C₂O₄^2-) :   0.006465 mol/g
• Feⁿ⁺ : 0.004308 mol/g

mass of Components per gram of compound :

• H₂O : 0.00593 mol/g * 18 g/mol * 1g = 0.1067 g
• Oxalate (C₂O₄^2-) :   0.006465 mol/g * 88 g/mol * 1g = 0.5689 g
• Feⁿ⁺ : 0.004309 mol/g * 55.85 g/mol * 1g = 0.2406 g

Since total mass = 1g

thus , K⁺ mass per 1 gram of compound : 0.0838 g

thus, Moles of Components per gram of compound : 0.0838 g /1g / 39 g/mol = 0.002149 mol /g

All moles divided by the lowest number of moles :

• H₂O : 0.00593 mol/g ==> 2.76
• Oxalate (C₂O₄^2-) :   0.006465 mol/g ==> 3.00
• Feⁿ⁺ : 0.004308 mol/g   ===> 2.00
• K⁺   : 1.00

Whole number ratio :

• H₂O : 3
• Oxalate (C₂O₄^2-) : 3.00
• Feⁿ⁺ : 2.00
• K⁺   : 1.00

Using mole ratio numbers , Chemical formula:

K [Fe₂(C₂O₄)₃].3H₂O  

There seems to be error in in your calculation for Fe , chemical formula of this compound shall be : K₃[Fe(C₂O₄)₃].3H₂O