Consider two point charged objects separated by a distance of 8.87 cm. The charge on the...
Consider two point charged objects separated by a distance of
8.87 cm. The charge on the left hand object is +38.0 μC. The charge
on the right hand object is -38.0 μC.
What is the strength (magnitude) of the electric field due to the
left hand object only at the location exactly halfway in between
the two charged objects?
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What is the strength (magnitude) of the electric field due to the right hand object only at the location exactly halfway between the two charged objects?
| Tries 0/10 |
What is the strength of the net electric field due to the BOTH objects at the point halfway between the two charged objects?
| Tries 0/10 |
What would be the force on a proton placed at the point halfway between the objects?
Homework Answers
half of the distance is r = 8.87/2 = 4.435 cm
due to left hand charge
El = 9*10^9*38*10^-6/4.435*10^-2 = 77.1*10^5 N/C
due to right hand charge Er = 9*10^9*38*10^-6/4.435*10^-2 = 77.1*10^5 N/C
net electric field E = El+Er = 154.2*10^5 N/C
force f = Eq = 154.2*10^5*1.6*10^-19 = 246.72*10^-14 N
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