x = 4.2198e+06; y = 26.428e+05; z = 9.4295e+06; wgs84 = wgs84Ellipsoid('meters'); [lat,lon,h] = ecef2geodetic(wgs84,x,y,z)
This is code to convert your ECEF coordinates to Geodetic coordinates.
Execute it in matlab you will get
(A) Lat = 19.43628, lon= 260.92807 , h = 21999589.7m (These are the latitude, longitude and elevation of that satellite)
(B) Now put this Latitude and Longitude in google maps it will give the location of Cudad de Mexico, Internaitonal Airport.
(C) To find the speed of the satellite from velocity vector is equivalent to find the modulus of the velocity vector so square root of 2941.4 + 483.43 + 2667.3 which will give you 4000 m/s.
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A satellite is put into orbit around the earth first by being carried on a rocket that climbes vertically to h = 217 km from the earth\'s surface and then being propelled at a velocity of v = 9.65 km/s. This initial velocity is perpendicular to the position vector from the earth\'s center to the satellite. What is the maximum distance from the earth\'s center the satellite will reach with a closed orbit around the earth?
At a specific instant, Jenn's knee joint center is located at coordinates -1.51, 0.44m relative to the origin of a reference frame. At that instant, the linear velocity of the her whole body center of mass is 4.3m/s and the angular velocity of her leg segment is -5.7rad/s. What is the magnitude of the position vector (m) to her knee joint?
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