A particle of mass 1.0 g is moving in a one-dimensional box of length 1.0 cm with a velocity 1.0 cm/s. Find its quantum number n.
THE KINETIC ENERGY OF PARTICLE IS EQUAL TO THE TOTAL ENERGY
m=.001kg,v=.01m/s,l=.01m
kinetic energy =1/2mv2
=1/2*.001*.01*.01
=5*10-8J
NOW THIS ENERGY MUST BE EQUAL TO THE ENERGY OF A PARTICLE IN ONE D BOX WHICH IS GIVEN BY
E=n2h2/8ml2
substituting values
5*10-8=n2h2/8ml2
n2 =5*10-8*8*.001*.01*.01/(6.26*10-34)2
FINALLY THE VALUE OF n is comes out to be 3*1026
A particle of mass 1.0 g is moving in a one-dimensional box of length 1.0 cm...
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