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1. An electron enters a uniform magnetic field of 2.5 mT with a velocity perpendicular to the direction of the field. At what
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Answer #1

Using Force balance on electron in magnetic field

Fc = Fm

m*V^2/R = q*V*B

V = q*B*R/m

Using given values:

V = 1.6*10^-19*2.5*10^-3*2.5*10^-2/(9.11*10^-31)

V = 10976948.4 m/sec

V = 1.10*10^7 m/sec = Speed of electron

Let me know if you've any query.

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