Using Force balance on electron in magnetic field
Fc = Fm
m*V^2/R = q*V*B
V = q*B*R/m
Using given values:
V = 1.6*10^-19*2.5*10^-3*2.5*10^-2/(9.11*10^-31)
V = 10976948.4 m/sec
V = 1.10*10^7 m/sec = Speed of electron
Let me know if you've any query.
1. An electron enters a uniform magnetic field of 2.5 mT with a velocity perpendicular to...
An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.12 mT. If the speed of the election is 1.63 x 107 m/s determine the followi (a) the radius of the circular path cm (b) the time interval required to complete one revolution An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.12 mT. If the speed of the election is 1.63 x 107 m/s...
An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.03 mT. If the speed of the electron is 1.66 x 107 m/s, determine the following (a) the radius of the circular path cm (b) the time interval required to complete one revolution
An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.13 mT. If the speed of the electron is 1.44 times 107 m/s, determine the following. (a) the radius of the circular path cm (b) the time interval required to complete one revolution s
A proton enters a region of constant magnetic field, perpendicular to the field and after being accelerated from rest by an electric field through an electrical potential difference of 470 V. Determine the magnitude of the magnetic field, if the proton travels in a circular path with a radius of 22 cm. 1.42e-3 How can you determine the speed at which the proton enters the region of constant magnetic field? What force provides the centripetal force that causes the proton...
A proton enters a region of constant magnetic field, perpendicular to the fie and after being accelerated from rest by an electric field through an electric potential difference of - 350 V. Determine the magnitude of the magnetic field, if the proton travels in a circular path with a radius of 21 cm. mt As shown in the figure below, when a charged particle enters a region of magnetic field traveling in a direction perpendicular to the field, it will...
An electron moves in a circular path perpendicular to a constant magnetic field with a magnitude of 1.00 mT. The angular momentum of the electron about the center of the circle is 2.50 times 10^-25 J-s. Determine the radius of the circular path. cm Determine the speed of the electron.
An electron enters a region of space containing a uniform 0.0000281-T magnetic field. Its speed is 121 m/s and it enters perpendicularly to the field. Under these conditions, the electron undergoes circular motion Find the radius r of the electron's path, and the frequency fof the motion. Number r- Number Hz f-
An electron has velocity V= (35i + 39j) km/s as it enters a uniform magnetic field B= 70i µT. What are (a) the radius of the helical path taken by the electron and (b) the pitch of that path? (c) To an observer looking into the magnetic field region from the entrance point of the electron, does the electron spiral clockwise or counterclockwise as it moves? The charge of an electron is -1.602 × 10^-19 C and its mass is...
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.210 T. If the kinetic energy of the electron is 2.20 x 10-19), find the speed of the electron and the radius of the circular path. (a) the speed of the electron m/s (b) the radius of the circular path um Additional Materials eBook -/1 Points) DETAILS SERCP10 19.P.038. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A mass spectrometer is used to examine the isotopes of...
An electron traveling left to right enters a region of space where a uniform magnetic field exists (see figure). Once in the field, the electron follows a circular path where r = 1.0E-6 m. If the magnitude of the magnetic field is 5.5 T, what is the speed of the electron and the direction of the magnetic field? 530 m/s, into the screen 530 m/s, out of the screen 9.7E5 m/s, into the screen 9.7E5 m/s, out of the screen...