Question

1) Carbon-14 is formed as the decay product of Nitrogen-15, which was formed when a cosmic ray bombards the N-15.

What is the particle equivalent of the cosmic ray involved in this decay process?

2) Carbon-14 get locked in organic material through this process.

3) How many half-lives of Carbon-14 decay will leave behind approximately 1/8 of the original mass of Carbon-14?

4) Using the equation for radioactive decay, if you start with one gram of radioactive substance that has a half-life of 24,500 years, how many years will it take for the substance to decay to 0.8 grams?

Answer 1

1(answer):- the particle equivalent of the cosmic ray involved in the decay process is Neutron.

2(answer):- when neutron collides with a nitrogen atom carbon 14 forms and that carbon 14 was absorbed by the plant by the process of photosynthesis.

3(answer):-no. Of haf lifes can be calculated as

(1/2)^n =1/8

So n=3

So no. Of half lifes are 3

4(answer):-

HALF LIFE = 0.693 2 Decay Constant 0.693 a (decay Constant) = 24,500 a = 2.82x10 Now & No= 1 gm N=0.89m IN= Noe at Putting Values in the given con + 0.8 = 1 e 28-28 X10 0.8= 2.828 x 10 x 2.32 8 x 10 x t = 1 43 2.8288 10 3 + lnt = ln 1.25 Int : 0.2231 - 0.0000288 in t = 0.2230 t = 1.2498

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