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The cylinder in the figure(Figure 1) has a moveable piston attached to a spring. The cylinders cross-section area is 10 cm”,

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Answer #1

The answer for above problem is explained below.

By using Ideal gas equation, . P; V; = nRT; - Vi = nRT; 3 V 0.0051 mol X 8.314 Jmoiik x (273+17)k 1.013X 105 Pa = V; = 1, 21And ff f = nR If ) Pi + DP) (V; + Ov) = nRTH z) 1.013 x16 Pa + (15 x10 9 Nov x)] [ 1. 21386 x104m? + 2 - (0.001m2)x] = 0.00 5

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