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K Chapter 16 Problem 16-5 cyclooctatetraene ▼ Part A This image shows that the first three pairs of electrons are in three bonding molecular orbitals of cyclooctatetraene. Electrons 7 and 8, however, are located in two different orbitals. As in cyclobutadiene, a planar cyclooctatetraene is predicted to be aa particularly unstable electron configuration. nonbonding; monoradical antibonding; monoradical nonbonding: diradical e antibonding; diradical Submit Request Answer

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problem 16 -5: Rightarrow cyclooctatetraene. Rightarrow cyclooctatetraene. * a circle, is inscribed with a polygon with one vertex pointing down , the vertices represent energy levels with the appropriate energies. * vertices below the halfway mark of the circle are considered bonding orbitals, and vertices above the halfway mark are considered anti - bonding orbitals . If vertices are exactly in the middle [as they are for 4- & 8- membered rings] they represent non - bonding orbitals. For example. 3-membered ring: n = 3 cycloproperium cation antibonding bonding Rightarrow 2 - pi (pi) electrons. 8 - membered ring: n = 8 cyclooctatetraene antibonding non - bonding bonding so, 7, 8 electrons are non - bonding orbitals. The molecular orbital levels predict from the polygon method this do not exactly correspond to the actual energy levels of cyclooctatetraene itself - It's not a diradical for instance. Just like anti aromatic cyclo but a diere can be made aromatic through the removal of two electrons. The stability of (theoretically antiaromatic) cyclooctatetraene can likewise be adjusted by the removal of addition