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(b) The graph of a parabola passes through the points (3/2,4/3) and (0, -6) and has a horizontal tangent line at (3/2,4/3). F

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SOLO the points : (², 4 and Parabola passes through СО) -ь) Horizontal tangent line at (3, 4) let be : the equation of Paraboy = az² + vrtu - 6 = axo the xoto c=-6, Put the value of c in equation ④ 4 / 3 = 2a + 2 w ub of a + 2 = 1 +6 function for hor바C을 1봉) dy o 20x3 + b =0 zat d=0 lub = -3a and in ean Put the solve value of for a and b we - qa = 22ON SOLVING we get a = -88/27

b = -3a

b = 88/9

so the equation of parabola is :

y = -88x2/27  + 88x/9 -6 .

graph :

- a

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