Plugging in given values,
/P = 100 x (K0.5 x 1000.5) - (10 x 100) - (1 x K)
/P = 100 x (10K0.5) - 1,000 - K
/P = 1,000K0.5 - 1,000 - K
Profit is maximized when d(/P)/dK = 0
1,000 x 0.5 x (1/K0.5) - 1 = 0
(500/K0.5) = 1
K0.5 = 500/1 = 500
Squaring both sides,
K = 250,000
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