For what value of a will P (−a < z < a) ≈ 0.90, and how...
For what value of a will P (−a < z < a) ≈ 0.90, and how will you shade a normal curve?
Homework Answers
For a normal standard curve, the image is bell-shaped and symmetrical.
P (−a < Z < a) ≈ 0.90 for this probability since the area is symmetrical and normal hence the area below -a and above a will be equal. Since the area of the middle curve is 0.90 hence the area outside the a and below -a will be (1-0.90)/2 = 0.05.
Thus the -a score is calculated using excel formula for normal distribution which is =NORM.S.INV(0.05) this results in -a = -1.645
and thus the right tail a score will be +1.645.
So, P (−1.645 < z < 1.645) ≈ 0.90
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ind the area of the shaded region under the standard distri z =-0.90-t t z 1.60...
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ind the area of the shaded region under the standard distri z =-0.90-t t z 1.60 2.5000 0.7611 0.9452 0.1841 2. Find the z score that corresponds to Po9, the 99th per curve O2.33 0.01 0.99 2.33 3. Following a standard normal distribution curve, find the a 0.0495 0.9500 0.9800 0.0500
11. In this exercise, you will learn about the 68-95-99.7 rule: Take the normal random variable X-N (14,'). (a) What is P(x-o <x<*+)? Hint: convert to Z. Draw the normal curve and shade in the corresponding probability. Answer: 0.683 (b) What is P(x - 20 < x < 1 + 20 )? Hint: convert to Z. Draw the normal curve and shade in the corresponding probability. Answer: 0.954 (c) What is P(x - 30 < X <H+ 30 )? Hint:...
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