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ggroune 4. (a) Determine the speed of a 60.0-kg woman at the bottom of a 21.9 m water slide, assuming there is no friction pr

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Answer #1

a)

using 3rd equation of motion

v^2 = 2 g h

v^2 = 2 * 9.8* 21.9

v = 20.718 m/s

====

b)

workdone = 0.5 m ( v^2 - u^2)

W = - 0.5* 60* ( 20.718^2 - 18^2)

W = - 3157.2 J

=======

Comment before rate in case any doubt, will reply for sure.. goodluck

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