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In the figure below (Figure 1), the upper ball is released from rest, collides with the stationary lower ball, and sticks toFigure < 1 of 1 > 10.0 cmPart A Find the frequency of the motion after the collision. Express your answer in hertz. IVO AD O O ? Submit Request AnswerPlease answer all parts with a clear explanation and work.

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A ) --.--- ® - - 10 cm D- - Potential energy of ball A = mgh = 2-30x9.8 X 10 x 102 = 9.254 J so according to conservation of=> 9.8*h = (0.595) 9. 8× h = (o. 575 2 = h = 60-575) 2x9.8 - 0.016 m. A l-47.5cm lcose Mitmet - ell-coso) I w.79.1 - feci-cos

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