Question

Can someone please solve the below lab in MATLAB showing the code and the output result as well please? Me and my partners cannot get our codes to give us the outputs.

10. The current flowing through a certain inductor is found to be given by i() = 0.20e-2- 0.6e-3t V. (a) Plot each of the two components over the range of 0 t 1.5 s. (b) Plot the inductor current over the same time range. (c) Plot the en- ergy remaining in the inductor (assuming inductance of 1 H) over 0 < t < 1.5 s.

Answer 1

The current flowing in the inductor is, ij(t)=0.2e-21 – 0.6e-31 A (a) Consider the first component of i, (t) which is 0.2e-21. Write the MATLAB code to sketch the first component 0.2e-2t over the range 0 St51.5s. t=0:0.01:1.5; IL=0.2*exp(-2*t); plot(t, IL) title('Figure 1') xlabel('Time (s)') ylabel('CurrentIL(A)').

0.18 0.16 CurrentIL(A) 0.06H 0.04 0.02 0.5 Timele) Figure 1 Consider the second component of i, (t) which is 0.6e-3t. Write the MATLAB code to sketch the first component 0.6e-3t over the range 0 St<1.5s.

t=0:0.01:1.5; IL=0.6*exp(-3*t); plot(t, IL) title ('Figure 2') xlabel('Time (s)'). ylabel('CurrentIL (A)') CurrentIL(A) Time(s) Figure 2

Write the MATLAB code to sketch iż (1) over the range 05t51.5s. t=0:0.01:1.5; IL=0.2*exp(-2*t)-0.6*exp(-3*t); plot(t, IL) title ('Figure 3'). xlabel('Time (s)'). ylabel('CurrentIL(A)').

CurrentIL(A) Time(s) Figure 3 (c) Given, L=1H. Calculate the energy stored in the inductor. E. ()=52,(1) =(1)[0.287 -0.6e"] = }[0.04e* +0.36€“ – 0.24e"] E; (t) = 0.02e™ +0.18e" – 0.12e-S'J

Write the MATLAB code to sketch energy remaining in the inductor over the range 0) <t<1.5s. t=0:0.01:1.5; EL=0.02*exp(-4*t) +0.18*exp(-6*t)- 0.12*exp(-5*t); plot(t,EL) title ('Figure 4'). xlabel('Time (s)'). ylabel('Energy (J)') 0.08 0.07H 0.06 0.05 Energy() 0.03 0.02 0.01 0.5 Time(s) Figure 4