The plot of ln[O3]/[O2] vs time is drawn and shown below. Time scale is taken as t*10-2
The rate constant from the slope is 0.054/100 =0.00054/sec
the equation of best fit is ln [O3]/[O3]o = -0.00054*t
Half life is the time required for the concentration to drop to 50% of its initial value.
ln 1/2 = -0.00054*t
t= 0.693/0.00054= 1283 seconds
from the best fit ln [O3]/[O3]o= -0.00054*t
[O3]/[O3]o =exp(-0.00054t)
d[O3]dt= -[O3]0 exp(-0.00054t)*0.00054
at t=0 -d[O3]/dt = 90*exp(-0.00054*0)*0.00054= 0.0486 uM/s
after 1.93 hrs, =1.93*60 minutes*60 seconds =6948 seconds
-d[O3]/dt = 90* exp(-0.00054*6948)* 0.00054=0.0011 uM/sec
the rate -dCA/dt= KCO3= K[O3]0*(1-XA)
hecne as the conversion changes the reaction rate also changes
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