Explain in detail what the code below does:
public class MyClass {
public static void main(String args[]) {
System.out.println(isUniqueChars("something"));
}
public static boolean isUniqueChars(String str) {
int checker = 0;
for (int i = 0; i < str.length(); ++i) {
int val = str.charAt(i) - 'a';
if ((checker & (1 << val)) > 0) return false;
checker |= (1 << val);
}
return true;
}
}
Answer:
This is the bitwise approach to check if the String str has all unique characters or not.
The approach is that, for every character in the string str,
a bit at an index is set inside the checker variable which is initially initialized to 0.
Example: If a is encountered inside the string, its index is considered as 0, b is considered as 1, c as 2 and so on.
Now, if a is encountered, 0th bit of the checker variable is checked using & operator. If it is already set, that means the character is being repeated, we return false directly.
Otherwise , we set the bit to 1 and proceed to next character.
This way, if no false is returned, true is returned at last.
PLEASE UPVOTE IF YOU FOUND THIS HELPFUL!
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