Homework Answers
Bi+2 + 2e- ---------> Bi
208.98 g Bi require 2 F electricity required
28 g Bi require 28 x 2 / 208.98 = 0.268 F electricity required
answer = 0.268 F electricity
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019 10.0 points An aqueous solution of bismuth nitrate (Bi(NO3)3) was electrolyzed until 28 grams of...
An aqueous solution of bismuth nitrate (Bi(NO3)3) was electrolyzed until 28 grams of metallic bismuth was...
An aqueous solution of bismuth nitrate (Bi(NO3)3) was electrolyzed until 28 grams of metallic bismuth was plated out at the cathode. How many Faradays of electricity must have passed through the cell?
5- An aqueous Ti(NO3)3 solution was electrolyzed for 45 min to deposit 6.18 grams of Titanium....
5- An aqueous Ti(NO3)3 solution was electrolyzed for 45 min to deposit 6.18 grams of Titanium. What is the constant current (in Amps) used in this electrolysis? (molar mass of Ti = 47.87 g/mol, Faraday Cte = 96,485 C/mole e")
An aqueous Snl, solution is electrolyzed under 1 bar pressure using platinum electrodes. (a) Write the...
An aqueous Snl, solution is electrolyzed under 1 bar pressure using platinum electrodes. (a) Write the half-reactions predicted to occur at the anode and cathode, based on the standard cell potentials given below. Standard Reduction Potentials (Volts) at 25°C 12(s) +2 — 21'(aq) 0.535 O2(g) + 4 H30* (aq) + 4 —6H20(1) 1.229 2 H20(1) + 2 € H2(g) + 2 OH'(aq) -0.828 Sn²+(aq) +2 € + Sn(s) -0.140 Half-reaction at anode: Half-reaction at cathode: (b) What is the expected...
5- An aqueous Ti(NO3)3 solution was electrolyzed for 45 min to deposit 6.18 grams of Titanium. What is the constant current (in Amps) used in this electrolysis? (molar mass of Ti = 47.87 g/mol, Faraday Cte = 96,485 C/mole e")
An aqueous Snl, solution is electrolyzed under 1 bar pressure using platinum electrodes. (a) Write the half-reactions predicted to occur at the anode and cathode, based on the standard cell potentials given below. Standard Reduction Potentials (Volts) at 25°C 12(s) +2 — 21'(aq) 0.535 O2(g) + 4 H30* (aq) + 4 —6H20(1) 1.229 2 H20(1) + 2 € H2(g) + 2 OH'(aq) -0.828 Sn²+(aq) +2 € + Sn(s) -0.140 Half-reaction at anode: Half-reaction at cathode: (b) What is the expected...
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