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How much volume of 0.2 M NaOH should be added to a How did they get these answers?
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Answer #1

12) At equivalence point,

   M1V1 = M2V2 [ M1,V1 refers to HCl and M2,V2 refers to NaOH ]

0.1 M x 30 mL = 0.2 M x V2

V2 = 0.1 M x 30 mL/ 0.2 M

= 15 mL

V2 = 15 mL

Therefore, volume of NaOH should be added = 15 mL

13)

[HCl ] = [H+] =  0.1 M x 30 mL = 3 mmol

[NaOH ] = [OH-] = 0.2 M x 15 mL = 3 mmol

Hence [H+] = [OH-],

this is the equivalence point and

thus,

     pH = 7.0

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