CH4 (g) + 2O2 (g) --> CO2 (g) + H2O(g) i. Calculate ∆rH0, ∆rS0, and ∆rG0...

Question

Question

CH₄ (g) + 2O₂ (g) --> CO₂ (g) + H₂O(g)

i. Calculate ∆_rH⁰, ∆_rS⁰, and ∆_rG⁰ for the reaction at 298.25 K

ii. Calculate the value of the equilibrium constant at 298.15 K

iii. Assuming ∆_rC⁰_P does not depend on temperature; calculate the value of the equilibrium constant at 498.15 K.

Answer 1

Answer #1

AHP any elemen tab it , ΔΗ 牙叉 --一名02-26 ki.. = ー-802-26 kJ , Pago 町 /k 包丁 213-68 o CS Givem, T 218 25 so, subshbute au tue

Answer 2

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