Question

Kuwait University Eng 207 Electrical Engincering Department Quiz 3 2142127 ag Vs DMM O0000 O0000 O0000 O0000 OOOD0 00odo ocódi To O0000 OOO00 OO000 O0000 O0000 SO000 00000 OOsco O0000 OOodo O0000 O0odo 00000 OO000 O0000 O0000 O0000 O00o0 oeod doco 00000 R O0000 OOOC Ra O00o0 O0000 00000 OO000 Given: R-2 K2, R 0.5 KQ, Ry 1 KQ, R ΚΩ, 1 VA8 Volt, Va 10 Volt For the given circuit, using superposition method, show your calculations in details to find: (6pts) 1) VR3' (VA only) (6pts) 2) VR" (VB only) 3) Assuming VR'-2 V and VRa"-5 V, Calculate: (2pts) (VA & Va) VR3 Draw the practical circuit diagram to measure Ig3 if (VA on and VgB shorted) (6pts) DMM A B Vs O0000 00000 O0000 00000 OO000 00000 O0000 00000 O0000 00000 OO000 O0000 O0000 O0000 O0000 O0000 O0000 O0000 O0000 O000 O0000 00000 O0000 O0000 00000 0000 O0000 00000 0000 O0000 00O00 000 O0000 O0000 O0000 O0000 O0000 O0000 O0000 O0000 00000 00000

Answer 1

Superposition Theorem:

In a linear active bilateral network consisting of number of sources and resistors etc, the response through any one of the element with respect to all the sources is equal to the sum of the responses due to all the sources each considered individually.

The given circuit can be rewritten as, RRkn V2Voll V& 1ov www R320.5ka Oseng Saperporton methed VP uhen Va is anly mesent shat circuit Vthen the ciscuit will be tere ww 1 kn 6-5ka CParaltet Combinatien 25x10 Ska 3 5K tse tak SV 22-140A 24mA get current flowing cument divisio of We knt aknt Oisn 14-2 doxi03 3 2 20 volk 3 x 10 x tkA TP's Now V

To find V when Ve esent Here VA is made short sivett, thun the circuit will be SIkn wwW len O.SKA thallka 0.ska 2 (ov Current 3O.ska 2-105105)a 10 mA 0 5kn 3kA to P3 is currenl dive seon the cumene 10 mA 22x 7 katlka voll VP3 Ve V3 S5 5 volt VP volVe t5 volt

Shorlec mearure and VA ON as that shorwn in The cicust Same duagiam will be Case () VA -8V 21kn k POrallel cembenaton of (2.ska) Il Ik kn Carent & V & V MA ta 3 55 1kA 2 knt 0,5 en +4 l0 mA Vue

While connecting the components on the bread board for the above circuit, it is said that V_{​​​​​​B} shorted. So connect another wire across the positive and negative terminals on B side of the network so that it becomes shorted